The equation of a stationary wave is given by $y = 5 \cos \left( \frac{\pi x}{3} \right) \sin (40 \pi t) \text{ cm}$. What is the distance between two consecutive nodes in $\text{cm}$?

$A$ progressive wave travelling in the positive $x$-direction is given by $y = a \sin(kx - \omega t)$. It meets a fixed end at $x = 0$. The reflected wave may be given by:

$A$ wave represented by the equation $y = a \cos (kx - \omega t)$ is superposed with another wave to form a stationary wave such that the point $x = 0$ is a node. The equation for the other wave is:

When a stationary wave is formed,what is its frequency compared to the individual waves that form it?

$A$ standing wave exists in a string of length $150 \ cm$,which is fixed at both ends with rigid supports. The displacement amplitude of a point at a distance of $10 \ cm$ from one of the ends is $5\sqrt{3} \ mm$. The nearest distance between two points,within the same loop and having a displacement amplitude equal to $5\sqrt{3} \ mm$,is $10 \ cm$. Find the maximum displacement amplitude of the particles in the string (in $mm$).

In a standing wave on a string $:-$