The work done in moving a charge of $20 \ C$ from point $A$ to point $B$ is $2 \ J$. What is the potential difference between the two points (in $V$)?

An electron of charge $e$ coulomb passes through a potential difference of $V$ volts. Its energy in joules will be

Four electric charges $+q, +q, -q$ and $-q$ are placed in order at the corners of a square of side $2r$. The electric potential at a point $P$ midway between the two negative charges is:

An electric charge $10^{-3} \mu C$ is placed at the origin of $x-y$ plane. The potential difference between points $A$ and $B$ located at $(\sqrt{2} m, \sqrt{2} m)$ and $(2 m, 0 m)$ respectively is (in $V$)

$A$ particle '$A$' has charge '$+q$' and a particle '$B$' has charge '$+4q$'. Each has the same mass '$m$'. When they are allowed to fall from rest through the same potential difference '$V$',the ratio of their speeds will be (particle $A$ to particle $B$):

$A$ particle of mass $m$ and charge $q$ is accelerated through a potential difference of $V$ volt. Its energy is