If a charge $Q$ is placed at the corner of a cube,what is the electric flux passing through one of its faces?

The electric field in a region is given by $\vec{E}=(2 \hat{i}+4 \hat{j}+6 \hat{k}) \times 10^3 \ N/C$. The flux of the field through a rectangular surface parallel to the $x-z$ plane is $6.0 \ N m^2 C^{-1}$. The area of the surface is . . . . . . $cm^2$.

Consider the charge configuration and spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface,the electric field will be due to:

In a certain region of space,there exists a uniform electric field of value $2 \times 10^2 \hat{k} \ Vm^{-1}$. $A$ rectangular coil of dimension $10 \ cm \times 20 \ cm$ is placed in the $xy$-plane. The electric flux through the coil is......$Vm$.

The wrong statement about electric lines of force is:

Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is $8.0 \times 10^{3} \; N m^{2} / C$.
$(a)$ What is the net charge inside the box?
$(b)$ If the net outward flux through the surface of the box were zero,could you conclude that there were no charges inside the box? Why or why not?