What is the equivalent capacitance between A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Identify the capacitors in series: The $2\ \mu F$ capacitor at the top and the $2\ \mu F$ capacitor on the right are in series. Their equival

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) $1$. Identify the capacitors in series: The $2\ \mu F$ capacitor at the top and the $2\ \mu F$ capacitor on the right are in series. Their equivalent capacitance is $C_s = \frac{2 	imes 2}{2 + 2} = 1\ \mu F$.$2$. Simplify the circuit: Replace these with a single $1\ \mu F$ capacitor. This new capacitor is in parallel with the $1\ \mu F$ capacitor connected diagonally. Their equivalent capacitance is $C_p = 1 + 1 = 2\ \mu F$.$3$. Further simplification: Now,this $2\ \mu F$ capacitor is in series with the $2\ \mu F$ capacitor at the bottom. Their equivalent capacitance is $C_s = \frac{2 	imes 2}{2 + 2} = 1\ \mu F$.$4$. Final step: This $1\ \mu F$ capacitor is in parallel with the $1\ \mu F$ capacitor connected directly between $A$ and $B$. The total equivalent capacitance is $C_{eq} = 1 + 1 = 2\ \mu F$.

What is the equivalent capacitance between $A$ and $B$ in the given circuit (in $\mu F$)?

Similar Questions

Obtain the formula for the effective capacitance of the parallel combination of $n$ capacitors.

Five capacitors are connected to a $DC$ potential of $100\,V$ as shown in the figure. Find the charge in the $10\,\mu F$ capacitor (in $\mu C$).

Find the net capacitance between $A$ and $B$.

In the arrangement of the capacitors as shown in the figure,each capacitor is of $6 \mu F$. Find the equivalent capacitance between points $A$ and $B$. (in $\mu F$)

Four identical capacitors are connected in series with a battery of $emf$ $10 \, V$. The point $X$ is earthed. Find the potential of point $A$. (in $, V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module