Find the potential difference $(V_A - V_B)$ for the given circuit.

In the given current distribution,what is the value of $I$ in $A$?

The current drawn from the battery in the given network is (Internal resistance of the battery is negligible). (in $A$)

Two resistances $R_1 = X \Omega$ and $R_2 = 1 \Omega$ are connected to a wire $AB$ of uniform resistivity,as shown in the figure. The radius of the wire varies linearly along its axis from $0.2 \text{ mm}$ at $A$ to $1 \text{ mm}$ at $B$. $A$ galvanometer $(G)$ connected to the center of the wire,$50 \text{ cm}$ from each end along its axis,shows zero deflection when $A$ and $B$ are connected to a battery. The value of $X$ is:

In the following diagram,the Wheatstone bridge is balanced when we interchange the resistances of:

In the following network,$I_{1} = -0.4 \text{ A}$,$I_{4} = 1 \text{ A}$ and $I_{5} = 0.4 \text{ A}$. The values of $I_{2}$,$I_{3}$ and $I_{6}$ respectively are: