In the given circuit,if no current flows thro | vedclass

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(A) The circuit represents a balanced Wheatstone bridge because no current flows through the central ammeter.For a balanced Wheatstone bridge,the rati

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(A) The circuit represents a balanced Wheatstone bridge because no current flows through the central ammeter.For a balanced Wheatstone bridge,the ratio of resistances in the arms must be equal: $\frac{X}{P} = \frac{R}{Q}$.Given $P = 20\,r$,$Q = 80\,r$,and $R = 1\,\Omega$.Substituting these values into the balance condition: $\frac{X}{20\,r} = \frac{1}{80\,r}$.Solving for $X$: $X = \frac{20\,r}{80\,r} = \frac{20}{80} = 0.25\,\Omega$.

In the given circuit,if no current flows through the ammeter,what is the value of $X$ in $\Omega$?

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