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(D) The magnetic field $B$ inside a toroid is given by the formula $B = \mu_0 n i$,where $n$ is the number of turns per unit length.Given: Radius $R =

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$5 	imes 10^{-4} \ T$

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(D) The magnetic field $B$ inside a toroid is given by the formula $B = \mu_0 n i$,where $n$ is the number of turns per unit length.Given: Radius $R = 0.1 \ m$,Number of turns $N = 500$,Current $i = 0.5 \ A$.The number of turns per unit length is $n = \frac{N}{2\pi R}$.Substituting the values: $n = \frac{500}{2\pi 	imes 0.1} = \frac{500}{0.2\pi} = \frac{2500}{\pi} \ m^{-1}$.Now,$B = (4\pi 	imes 10^{-7}) 	imes \left(\frac{2500}{\pi}ight) 	imes 0.5$.$B = 4 	imes 10^{-7} 	imes 2500 	imes 0.5$.$B = 4 	imes 10^{-7} 	imes 1250$.$B = 5000 	imes 10^{-7} \ T = 5 	imes 10^{-4} \ T$.

What is the magnetic field inside a toroid having $0.1 \ m$ radius and $500$ turns when a current of $0.5 \ A$ is passed through it?

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