When light of frequencies ${\nu _1}$ and ${\nu _2}$ $({\nu _1} > {\nu _2})$ is incident on a metal surface,the ratio of the maximum kinetic energy of the emitted photoelectrons is $1:k$. What is the threshold frequency of the metal?

  • A
    $\frac{{{\nu _1} - {\nu _2}}}{{k - 1}}$
  • B
    $\frac{{k{\nu _2} - {\nu _1}}}{{k - 1}}$
  • C
    $\frac{{k{\nu _1} - {\nu _2}}}{{k - 1}}$
  • D
    $\frac{{{\nu _2} - {\nu _1}}}{{k - 1}}$

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