What is the ratio of the radii of the nuclei | vedclass

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(A) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number.Therefore,the ratio of the

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$3:5$

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(A) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number.Therefore,the ratio of the radii of two nuclei is given by $\frac{R_1}{R_2} = \left( \frac{A_1}{A_2} \right)^{1/3}$.For $_{13}^{27}Al$,the mass number $A_1 = 27$.For $_{52}^{125}Te$,the mass number $A_2 = 125$.Substituting these values into the ratio formula:$\frac{R_1}{R_2} = \left( \frac{27}{125} \right)^{1/3} = \frac{(3^3)^{1/3}}{(5^3)^{1/3}} = \frac{3}{5}$.Thus,the ratio of the radii is $3:5$.

What is the ratio of the radii of the nuclei $_{13}^{27}Al$ and $_{52}^{125}Te$?

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