The Avogadro number is 6 times 10^{23}. What | vedclass

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(A) The atomic mass of $_6C^{14}$ is $14 \, g/mol$.The number of moles in $14 \, g$ of $_6C^{14}$ is $n = \frac{14 \, g}{14 \, g/mol} = 1 \, mol$.The

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$36 	imes 10^{23}, 48 	imes 10^{23}, 36 	imes 10^{23}$

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(A) The atomic mass of $_6C^{14}$ is $14 \, g/mol$.The number of moles in $14 \, g$ of $_6C^{14}$ is $n = \frac{14 \, g}{14 \, g/mol} = 1 \, mol$.The number of atoms in $1 \, mol$ is equal to the Avogadro number,$N_A = 6 	imes 10^{23}$.In one atom of $_6C^{14}$:Protons $(Z)$ = $6$Neutrons $(N = A - Z)$ = $14 - 6 = 8$Electrons = $6$ (since it is a neutral atom).Total number of protons = $6 	imes (6 	imes 10^{23}) = 36 	imes 10^{23}$.Total number of neutrons = $8 	imes (6 	imes 10^{23}) = 48 	imes 10^{23}$.Total number of electrons = $6 	imes (6 	imes 10^{23}) = 36 	imes 10^{23}$.

The Avogadro number is $6 \times 10^{23}$. What will be the number of protons,neutrons,and electrons in $14 \, g$ of $_6C^{14}$?

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