In the given circuit,what happens when the sw | vedclass

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(C) When the switch $S$ is opened,the circuit containing the resistor $R$ and bulb $B_1$ is broken immediately,so the current through $B_1$ drops to z

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Bulb $B_1$ turns off immediately,while bulb $B_2$ turns off after some time.

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(C) When the switch $S$ is opened,the circuit containing the resistor $R$ and bulb $B_1$ is broken immediately,so the current through $B_1$ drops to zero instantly,and it turns off.However,the inductor $L$ opposes the change in current. Due to self-induction,it maintains the current in the loop containing the inductor $L$ and bulb $B_2$ for a short duration as the magnetic field energy stored in the inductor decays. Thus,the current through $B_2$ decreases gradually,causing it to turn off after some time.

In the given circuit,what happens when the switch $S$ is opened?

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