A square loop of side 0.1 , m and resistance | vedclass

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(B) The external circuit is a balanced Wheatstone bridge. The resistance of the bridge between points $P$ and $Q$ is $R_{ext} = 3 \, \Omega$.The total

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$2$

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(B) The external circuit is a balanced Wheatstone bridge. The resistance of the bridge between points $P$ and $Q$ is $R_{ext} = 3 \, \Omega$.The total resistance of the circuit is $R = R_{loop} + R_{ext} = 1 \, \Omega + 3 \, \Omega = 4 \, \Omega$.The induced electromotive force $(EMF)$ is given by $e = Bvl$.Using Ohm's law, $i = \frac{e}{R} = \frac{Bvl}{R}$.Given $i = 1 \, mA = 10^{-3} \, A$, $B = 2 \, Wb/m^2$, $l = 0.1 \, m$, and $R = 4 \, \Omega$.Substituting the values: $10^{-3} = \frac{2 	imes v 	imes 0.1}{4}$.$10^{-3} = \frac{0.2 	imes v}{4} = 0.05 	imes v$.$v = \frac{10^{-3}}{0.05} = 0.02 \, m/sec = 2 \, cm/sec$.

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