A light ray is incident on a spherical glass | vedclass

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(B) At the first point of incidence $B$,the angle of deviation is $\delta_1 = (\alpha - \beta)$.At the second point of refraction $C$,the ray is incid

Vedclass · Accepted Answer

$2\left( {\alpha - \beta } \right)$

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(B) At the first point of incidence $B$,the angle of deviation is $\delta_1 = (\alpha - \beta)$.At the second point of refraction $C$,the ray is incident at angle $\beta$ and emerges at angle $\alpha$ due to symmetry.The angle of deviation at point $C$ is $\delta_2 = (\alpha - \beta)$.The total angle of deviation $\delta$ is the sum of the deviations at both points:$\delta = \delta_1 + \delta_2 = (\alpha - \beta) + (\alpha - \beta) = 2(\alpha - \beta)$.

$A$ light ray is incident on a spherical glass surface at an angle $\alpha$ and is refracted at an angle $\beta$. What is the angle of deviation between the emergent ray and the incident ray?

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