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(A) For the face $AB$,the angle of incidence $i = 0$,so the angle of refraction $r = 0$. The light enters the prism undeviated.For the face $AC$,the a

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Separates the red color from the green and blue colors.

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(A) For the face $AB$,the angle of incidence $i = 0$,so the angle of refraction $r = 0$. The light enters the prism undeviated.For the face $AC$,the angle of incidence is $i = 45^\circ$. Total internal reflection occurs if $i > 	heta_C$,where $	heta_C$ is the critical angle.Condition for total internal reflection: $\sin i > \sin 	heta_C \implies \sin 45^\circ > \frac{1}{\mu} \implies \mu > \frac{1}{\sin 45^\circ} = \sqrt{2} \approx 1.41$.Given refractive indices: $\mu_R = 1.39$,$\mu_G = 1.44$,and $\mu_B = 1.47$.Since $\mu_R Since $\mu_G > 1.41$ and $\mu_B > 1.41$,both green and blue light will undergo total internal reflection at face $AC$.Therefore,the prism separates the red color from the green and blue colors.

$A$ beam containing red,green,and blue light is incident on a prism. Their refractive indices are $1.39, 1.44$,and $1.47$ respectively. Then,the prism:

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