A substance is soluble in concentrated H_2SO_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The substance is soluble in concentrated $H_2SO_4$,which indicates it could be an alcohol,alkene,or ether. Since it does not decolorize bromine in

Vedclass · Accepted Answer

Primary alcohol

Vedclass · Answer

(D) The substance is soluble in concentrated $H_2SO_4$,which indicates it could be an alcohol,alkene,or ether. Since it does not decolorize bromine in $CCl_4$,it is not an alkene. Ethers are generally resistant to oxidation by chromic anhydride in aqueous $H_2SO_4$ (Jones reagent). Primary alcohols are oxidized very rapidly by chromic anhydride in aqueous $H_2SO_4$ (Jones oxidation),which matches the observed color change (orange $Cr^{6+}$ to green/blue $Cr^{3+}$). Therefore,the substance is a primary alcohol.

$A$ substance is soluble in concentrated $H_2SO_4$. It does not decolorize a solution of bromine in $CCl_4$. However,it is oxidized by chromic anhydride in aqueous sulfuric acid in just two seconds,changing the orange solution to blue,green,and then opaque. What does the original solution contain?

Similar Questions

The major product obtained by the dehydration of the given alcohol is $:-$

Compound '$A$' reacts with $PCl_5$ to give '$B$',which on treatment with $KCN$ followed by hydrolysis gives propanoic acid as the product. What is '$A$'?

When benzyl alcohol is oxidised with $KMnO_4$,the product obtained is

Explain the intermolecular hydrogen bonding in alcohols and phenols and its effect on their physical properties.

The reaction of $4-(\text{aminomethyl})\text{cyclohexylmethanol}$ with acetic anhydride $(Ac_2O)$ proceeds in two steps to form $P$ and $Q$. Identify $P$ and $Q$ respectively.

Vedclass Test Series

Exam Paper Generator

Online Exam Module