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(D) The reaction of a Grignard reagent $(RMgX)$ with ethylene oxide (epoxide) involves the nucleophilic attack of the $R^-$ group on one of the carbon

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$RCH_2CH_2OH$

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(D) The reaction of a Grignard reagent $(RMgX)$ with ethylene oxide (epoxide) involves the nucleophilic attack of the $R^-$ group on one of the carbon atoms of the epoxide ring,leading to ring opening.$RMgX + CH_2-CH_2(O) 	o R-CH_2-CH_2-OMgX$Subsequent hydrolysis of the intermediate alkoxide yields a primary alcohol:$R-CH_2-CH_2-OMgX + H_2O 	o R-CH_2-CH_2-OH + Mg(OH)X$Thus,the final product is $RCH_2CH_2OH$.

What is the product obtained when the reaction of $CH_2-CH_2$ (epoxide) with $RMgX$ is followed by hydrolysis?

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