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(D) The reaction sequence is as follows:$1$. Ethene $(CH_2=CH_2)$ reacts with $O_2$ in the presence of $Ag$ catalyst to form epoxyethane $(X)$: $CH_2=

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Ethylene glycol

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(D) The reaction sequence is as follows:$1$. Ethene $(CH_2=CH_2)$ reacts with $O_2$ in the presence of $Ag$ catalyst to form epoxyethane $(X)$: $CH_2=CH_2 + \frac{1}{2}O_2 \xrightarrow{Ag} C_2H_4O$ (Epoxyethane).$2$. Epoxyethane $(X)$ upon heating at $473 \ K$ (usually in the presence of water/acidic medium) undergoes hydration to form ethylene glycol $(Y)$:$C_2H_4O + H_2O \xrightarrow{473 \ K} HO-CH_2-CH_2-OH$ (Ethylene glycol).Thus,the final product $Y$ is ethylene glycol.

Identify the final product $Y$ in the following reaction sequence:
$CH_2 = CH_2$ $\xrightarrow{O_2/Ag} X$ $\xrightarrow{473 \ K} Y$

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Identify the final product $Y$ in the following reaction sequence:$CH_2 = CH_2$ $\xrightarrow{O_2/Ag} X$ $\xrightarrow{473 \ K} Y$