What will be the product of the reaction with $HBr$?

  • A
    $CH_3CHBrCH_2-C_6H_4-OH$
  • B
    $CH_3CH_2CH(Br)-C_6H_4-OH$
  • C
    $CH_3CHBrCH_2-C_6H_4-Br$
  • D
    $CH_3CH_2CHBr-C_6H_4-OH$

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