When diethyl ether is reacted with an excess | vedclass

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(C) When diethyl ether $(CH_3CH_2-O-CH_2CH_3)$ reacts with an excess of chlorine $(Cl_2)$ in the presence of sunlight $(hv)$,all the hydrogen atoms ar

Vedclass · Accepted Answer

$CCl_3CCl_2-O-CCl_2CCl_3$

Vedclass · Answer

(C) When diethyl ether $(CH_3CH_2-O-CH_2CH_3)$ reacts with an excess of chlorine $(Cl_2)$ in the presence of sunlight $(hv)$,all the hydrogen atoms are replaced by chlorine atoms.The chemical reaction is:$CH_3CH_2-O-CH_2CH_3 + 10Cl_2 \xrightarrow{hv} CCl_3CCl_2-O-CCl_2CCl_3 + 10HCl$Thus,the final product is perchlorodiethyl ether,which is $CCl_3CCl_2-O-CCl_2CCl_3$.

When diethyl ether is reacted with an excess of chlorine in the presence of sunlight,what is the final product obtained?

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