What will be the compound $X$ in the given reaction?
$MeO-C_6H_4-CHO + (X) \xrightarrow{CH_3COONa, H_3O^+} MeO-C_6H_4-CH=CHCOOH$

  • A
    $CH_3COOH$
  • B
    $BrCH_2-COOH$
  • C
    $(CH_3CO)_2O$
  • D
    $CHO-COOH$

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