Which of the following is the correct order of acidic strength?

  • A
    $RCOOH > HC \equiv CH > HOH > ROH$
  • B
    $RCOOH > ROH > HOH > HC \equiv CH$
  • C
    $RCOOH > HOH > ROH > HC \equiv CH$
  • D
    $RCOOH > HOH > HC \equiv CH > ROH$

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What is the final product $(B)$ of this sequence?

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Find the missing information from the following reactions:
$(i)$ $CH_3COOH \rightarrow[\Delta]{H_2SO_4/P_2O_5} ?$
$(ii)$ $? + CH_3OH \rightleftharpoons[H^{+}]{} CH_3COOCH_3 + H_2O$
$(iii)$ $3 CH_3COOH + PCl_3 \rightarrow 3 CH_3COCl + ?$
$(iv)$ $CH_3COOH + PCl_5 \rightarrow CH_3COCl + ? + HCl$
$(v)$ $C_6H_5COONa \rightarrow{?} C_6H_6$
$(vi)$ $CH_3CH_2COOH \rightarrow{\text{excess } Br_2 + \text{Red } P} ? + ?$
$(vii)$ $CH_3CH_2COOH \rightarrow{?} CH_3CH_2CH_2OH$
$(viii)$ $C_6H_5COOH \rightarrow{\text{anhydrous } AlCl_3, CH_3Cl \text{ or } CH_3COCl} ?$

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An organic compound having molecular formula $C_2H_6O$ undergoes oxidation with $K_2Cr_2O_7 / H_2SO_4$ to produce $X$ which contains $40\,\%$ carbon,$6.7\,\%$ hydrogen and $53.3\,\%$ oxygen. The molecular formula of the compound $X$ is

Hence the product $(Y)$ in the above sequence of reactions,is

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$\text{CH}_3\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{X} \xrightarrow{\text{PCl}_5} \text{Y} \xrightarrow{\text{Alcoholic KOH}} \text{Z}$. Find product '$Z$' in the above reaction.

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