When mesityl oxide undergoes the iodoform rea | vedclass

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Question

(C) Mesityl oxide is $(CH_3)_2C=CH-CO-CH_3$. It contains a methyl ketone group $(-COCH_3)$,which undergoes the iodoform reaction with $I_2$ and $NaOH$

Vedclass · Accepted Answer

$(CH_3)_2C=CH-COOH$

Vedclass · Answer

(C) Mesityl oxide is $(CH_3)_2C=CH-CO-CH_3$. It contains a methyl ketone group $(-COCH_3)$,which undergoes the iodoform reaction with $I_2$ and $NaOH$. The reaction is: $(CH_3)_2C=CH-CO-CH_3 + 3I_2 + 4NaOH \rightarrow (CH_3)_2C=CH-COONa + CHI_3 + 3NaI + 3H_2O$. The organic acid salt formed is sodium salt of $3-$methylbut$-2-$enoic acid. Therefore,the corresponding acid is $(CH_3)_2C=CH-COOH$.

When mesityl oxide undergoes the iodoform reaction,one of the products obtained is a sodium salt of an organic acid. Which acid is formed?

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