The dissociation constants (K_a) of four acid | vedclass

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(A) The strength of an acid is directly proportional to its dissociation constant $(K_a)$.Comparing the given values:$A = 2 	imes 10^{-2} = 0.02$$B =

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$2 	imes 10^{-2}$

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(A) The strength of an acid is directly proportional to its dissociation constant $(K_a)$.Comparing the given values:$A = 2 	imes 10^{-2} = 0.02$$B = 0.02 	imes 10^{-1} = 0.002$$C = 3 	imes 10^{-4} = 0.0003$$D = 2 	imes 10^{-4} = 0.0002$Since $0.02$ is the largest value,the acid with $K_a = 2 	imes 10^{-2}$ is the strongest.

The dissociation constants $(K_a)$ of four acids are given below. Which of these is the strongest acid?

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