M_n and M_p represent the mass of a neutron a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The actual mass of a nucleus $(M)$ is always less than the sum of the individual masses of its constituent nucleons (protons and neutrons).This di

Vedclass · Accepted Answer

$M  <  [N M_n + Z M_p]$

Vedclass · Answer

(A) The actual mass of a nucleus $(M)$ is always less than the sum of the individual masses of its constituent nucleons (protons and neutrons).This difference in mass is known as the mass defect $(\Delta m)$, which is converted into binding energy according to Einstein's mass-energy equivalence principle $(E = \Delta m c^2)$.Therefore, the mass of the nucleus $M$ is related to the sum of the masses of $N$ neutrons and $Z$ protons as:$M  <  (N M_n + Z M_p)$.

$M_n$ and $M_p$ represent the mass of a neutron and a proton, respectively. If an element having atomic mass $M$ has $N$ neutrons and $Z$ protons, then the correct relation is:

Similar Questions

What is mass defect? Write down its formula.

The positions of four different nuclei in the binding energy curve are shown in the figure. The process that might not proceed spontaneously is

The binding energy of a nucleon in a nucleus is of the order of a few

The mass defect in a particular nuclear reaction is $0.3 \,g$. The amount of energy liberated in kilowatt-hour $(kWh)$ is: (Velocity of light $c = 3 \times 10^8 \,m/s$)

The dependence of binding energy per nucleon,$B_N$ on the mass number,$A$,is represented by

Vedclass Test Series

Exam Paper Generator

Online Exam Module