(D) . $F^-$ is the strongest reducing agent among halides,but $F_2$ is the strongest oxidizing agent. The oxidation of $F^-$ to $F_2$ is not possible

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(D) . $F^-$ is the strongest reducing agent among halides,but $F_2$ is the strongest oxidizing agent. The oxidation of $F^-$ to $F_2$ is not possible by any chemical oxidizing agent because the standard oxidation potential of $F^-$ is very low (highly negative). Therefore,$F^-$ can be oxidized to $F_2$ only by electrolysis.

Class 12 Chemistry p-Block Elements (Class 12)Halogen family

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$HBr$ and $HI$ can reduce $H_2SO_4$,$HCl$ can reduce $KMnO_4$,and $HF$ can reduce:

IIT 1981 All IIT

A
$H_2SO_4$
B
$KMnO_4$
C
$K_2Cr_2O_7$
D
None of the above

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Halogen family

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$HBr$ and $HI$ can reduce $H_2SO_4$,$HCl$ can reduce $KMnO_4$,and $HF$ can reduce:

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