p-cresol reacts with chloroform in an alkalin | vedclass

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(B) $p$-cresol reacts with $CHCl_3$ in an alkaline medium (Reimer-Tiemann reaction) to form $2$-hydroxy-$5$-methylbenzaldehyde (compound $A$).Compound

Vedclass · Accepted Answer

$2-$hydroxy$-5-$methylmandelic acid (with correct structure)

Vedclass · Answer

(B) $p$-cresol reacts with $CHCl_3$ in an alkaline medium (Reimer-Tiemann reaction) to form $2$-hydroxy-$5$-methylbenzaldehyde (compound $A$).Compound $A$ reacts with $HCN$ to form a cyanohydrin,$2$-hydroxy-$5$-methylmandelonitrile (compound $B$).Acidic hydrolysis of the cyanohydrin $(B)$ yields $2$-hydroxy-$5$-methylmandelic acid,which is a chiral carboxylic acid due to the presence of a chiral carbon atom at the $\alpha$-position.The structure is $2$-hydroxy-$5$-methylmandelic acid,which corresponds to the structure shown in option $B$.

$p$-cresol reacts with chloroform in an alkaline medium to give compound $A$,which adds hydrogen cyanide to form compound $B$. The latter,on acidic hydrolysis,gives a chiral carboxylic acid. The structure of the carboxylic acid is:

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