If A and B are disjoint sets,then n(A cup B) | vedclass

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(C) Two sets $A$ and $B$ are said to be disjoint if they have no common elements,i.e.,$A \cap B = \emptyset$.For any two finite sets $A$ and $B$,the f

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$n(A) + n(B)$

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(C) Two sets $A$ and $B$ are said to be disjoint if they have no common elements,i.e.,$A \cap B = \emptyset$.For any two finite sets $A$ and $B$,the formula for the number of elements in their union is given by:$n(A \cup B) = n(A) + n(B) - n(A \cap B)$.Since $A$ and $B$ are disjoint,$n(A \cap B) = 0$.Therefore,$n(A \cup B) = n(A) + n(B) - 0 = n(A) + n(B)$.

If $A$ and $B$ are disjoint sets,then $n(A \cup B) = $

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