$_{90}^{232}Th$,an isotope of thorium,decays in ten stages,emitting six $\alpha$-particles and four $\beta$-particles in total. The end product of the decay is:

When a nucleus with atomic number $Z$ and mass number $A$ undergoes a radioactive decay process:

Consider the following radioactive decay process:
${ }_{84}^{218} A \stackrel{\alpha}{\longrightarrow} A_1 \stackrel{\beta^{-}}{\longrightarrow} A_2 \stackrel{\gamma}{\longrightarrow} A_3 \stackrel{\alpha}{\longrightarrow} A_4 \stackrel{\beta^{+}}{\longrightarrow} A_5 \stackrel{\gamma}{\longrightarrow} A_6$
The mass number and the atomic number of $A_6$ are given by:

Which of the following statements is true?

Which of the following will have the highest penetrating power?

An artificial radioactive decay series begins with unstable $_{94}^{241}Pu$. The stable nuclide obtained after eight $\alpha$-decays and five $\beta$-decays is