(C) For a wheel rolling without slipping,the velocity of the center of mass is $v = r\omega$. The velocity of the highest point of the wheel is $v_{to

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(C) For a wheel rolling without slipping,the velocity of the center of mass is $v = r\omega$. The velocity of the highest point of the wheel is $v_{top} = v + r\omega = v + v = 2v$. Since the bicycle moves as a single rigid body,the velocity of the center of mass $(v)$ is the same for both the front and rear wheels. Therefore,$v_F = 2v$ and $v_r = 2v$. Thus,$v_F = v_r$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

In a bicycle,the radius of the rear wheel is twice the radius of the front wheel. If $r_F$ and $r_r$ are the radii,and $v_F$ and $v_r$ are the velocities of the highest points of the front and rear wheels respectively,then:

A
$v_r = 2 v_F$
B
$v_F = 2 v_r$
C
$v_F = v_r$
D
$v_F > v_r$

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In a bicycle,the radius of the rear wheel is twice the radius of the front wheel. If $r_F$ and $r_r$ are the radii,and $v_F$ and $v_r$ are the velocities of the highest points of the front and rear wheels respectively,then:

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The transformed equation of $3x^2 - 4xy = r^2$ when the coordinate axes are rotated about the origin through an angle of $\operatorname{Tan}^{-1}(2)$ in the positive direction is:

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If the line $\vec{r} = (\hat{i} - 2\hat{j} - \hat{k}) + \lambda (2\hat{i} + \hat{j} + 2\hat{k})$ is parallel to the plane $\vec{r} \cdot (3\hat{i} - 2\hat{j} - m\hat{k}) = 14$,then the value of $m$ is:

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