The moment of inertia of a ring of mass $M$ and radius $R$ about an axis passing through its center and perpendicular to its plane is:

  • A
    $ \frac{1}{2}M{R^2} $
  • B
    $ M{R^2} $
  • C
    $ \frac{1}{4}M{R^2} $
  • D
    $ \frac{3}{4}M{R^2} $

Explore More

Similar Questions

Can the moment of inertia of the same body be different?

The moment of inertia of a sphere of mass $M$ and radius $R$ about an axis passing through its centre is $\frac{2}{5} M R^2$. The radius of gyration of the sphere about a parallel axis to the above and tangent to the sphere is

If the length of a thin uniform rod is $L$ and the radius of gyration of the rod about an axis perpendicular to its length and passing through one end is $K$, then $K: L=$

The moment of inertia of a body does not depend on

$A$ body of mass $m$ and radius of gyration $K$ has an angular momentum $L$. Then its angular velocity is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo