(D) Given: Mass $m = 10 \, kg$,Diameter $D = 0.2 \, m$,Radius $r = D/2 = 0.1 \, m$,Acceleration due to gravity $g = 9.8 \, m/s^2$.Since the body is at

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(D) Given: Mass $m = 10 \, kg$,Diameter $D = 0.2 \, m$,Radius $r = D/2 = 0.1 \, m$,Acceleration due to gravity $g = 9.8 \, m/s^2$.Since the body is at rest,the tension $T$ in the rope is equal to the weight of the body: $T = mg = 10 \times 9.8 = 98 \, N$.The torque $\tau$ applied about the horizontal axis of the cylinder is given by: $\tau = r \times T$.Substituting the values: $\tau = 0.1 \times 98 = 9.8 \, N-m$.

Class 11 Physics System of Particles and Rotational Motion Torque and Couple

Easy

$A$ body of mass $10 \, kg$ is hanging at rest with the help of a rope wrapped around a cylinder of diameter $0.2 \, m$. The torque applied about the horizontal axis of the cylinder is ....... $N-m$.

A
$98$
B
$19.6$
C
$196$
D
$9.8$

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Class 11

Physics Questions

Chapter

System of Particles and Rotational Motion

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Torque and Couple

Let $\vec{F}$ be a force acting on a particle having position vector $\vec{r}$,and $\vec{\tau}$ be the torque of this force about the origin. Then:

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Four equal and parallel forces are acting on a rod (as shown in the figure) at distances of $20 \, cm, 40 \, cm, 60 \, cm$,and $80 \, cm$ respectively from one end of the rod. Under the influence of these forces,the rod -

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$A$ force of $(2\hat i - 4\hat j + 2\hat k) \ N$ acts at a point $(3\hat i + 2\hat j - 4\hat k) \ m$ from the origin. The magnitude of torque is ......... $N-m$.

Medium

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How is the direction of torque determined?

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$A$ force of $-P \hat{k}$ acts on the origin of the coordinate system. The torque about the point $(2, -3)$ is $P(a \hat{i} + b \hat{j})$. If the ratio $\frac{a}{b} = \frac{x}{2}$,find the value of $x$.

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$A$ body of mass $10 \, kg$ is hanging at rest with the help of a rope wrapped around a cylinder of diameter $0.2 \, m$. The torque applied about the horizontal axis of the cylinder is ....... $N-m$.

Similar Questions

Let $\vec{F}$ be a force acting on a particle having position vector $\vec{r}$,and $\vec{\tau}$ be the torque of this force about the origin. Then:

Four equal and parallel forces are acting on a rod (as shown in the figure) at distances of $20 \, cm, 40 \, cm, 60 \, cm$,and $80 \, cm$ respectively from one end of the rod. Under the influence of these forces,the rod -

$A$ force of $(2\hat i - 4\hat j + 2\hat k) \ N$ acts at a point $(3\hat i + 2\hat j - 4\hat k) \ m$ from the origin. The magnitude of torque is ......... $N-m$.

How is the direction of torque determined?

$A$ force of $-P \hat{k}$ acts on the origin of the coordinate system. The torque about the point $(2, -3)$ is $P(a \hat{i} + b \hat{j})$. If the ratio $\frac{a}{b} = \frac{x}{2}$,find the value of $x$.

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