The rotational effect is produced by

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The torque $\vec{	au}$ is defined as the cross product of the position vector $\vec{r}$ and the force vector $\vec{F}$:$\vec{	au} = \vec{r} 	im

Vedclass · Accepted Answer

the transverse component of the force

Vedclass · Answer

(C) The torque $\vec{	au}$ is defined as the cross product of the position vector $\vec{r}$ and the force vector $\vec{F}$:$\vec{	au} = \vec{r} 	imes \vec{F}$The magnitude of the torque is given by $	au = r F \sin \phi$,where $\phi$ is the angle between the position vector $\vec{r}$ and the force vector $\vec{F}$.In this expression,$F \sin \phi$ represents the component of the force perpendicular to the position vector,which is known as the transverse component.The radial component $F \cos \phi$ acts along the line of the position vector and does not contribute to the rotational effect (torque).Therefore,the rotational effect is produced by the transverse component of the force.

Similar Questions

Show that the moment of a couple does not depend on the point about which you take the moments.

$A$ slab is subjected to two forces $\vec F_1$ and $\vec F_2$ of the same magnitude $F$ as shown in the figure. Force $\vec F_2$ is in the $XY$-plane,while force $\vec F_1$ acts along the $z$-axis at the point $(2\hat i + 3\hat j)$. The moment of these forces about point $O$ is:

$A$ particle of mass $m$ is moving along a trajectory given by $x = x_0 + a \cos \omega_1 t$ and $y = y_0 + b \sin \omega_2 t$. The torque acting on the particle about the origin at $t = 0$ is:

Which physical quantity plays the same role in rotational motion as force does in linear motion?

Find the torque about the origin when a force of $3 \hat{j} \text{ N}$ acts on a particle whose position vector is $2 \hat{k} \text{ m}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module