What is the ratio of the rotational kinetic energy to the translational kinetic energy of a solid sphere?

$A$ flywheel is making $\frac{3000}{\pi}$ revolutions per minute about its axis. If the moment of inertia of the flywheel about that axis is $400 \ kg \ m^2$,its rotational kinetic energy is

Two bodies $A$ and $B$ have their moments of inertia $I_1$ and $I_2$ respectively about their axis of rotation. If their kinetic energies of rotation are equal and their angular momenta $L_1$ and $L_2$ respectively are in the ratio $1 : \sqrt{3}$,then $I_2$ will be

$A$ flywheel of moment of inertia $0.32 \ kg \cdot m^2$ is rotated steadily at $120 \ rad/s$ by a $50 \ W$ electric motor. The kinetic energy of the flywheel is .......... $J$.

Two rotating bodies $A$ and $B$ of masses $m$ and $2m$ with moments of inertia $I_A$ and $I_B$ $(I_B > I_A)$ have equal kinetic energy of rotation. If $L_A$ and $L_B$ are their angular momenta respectively,then:

The rotational kinetic energy of an object is $E$ and its moment of inertia is $I$. The angular momentum of the object will be: