A circular platform is situated in a horizont | vedclass

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(B) Since there is no external torque acting on the system,the angular momentum $L = I\omega$ remains constant. As the tortoise moves along a chord,it

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The angular velocity first increases and then decreases.

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(B) Since there is no external torque acting on the system,the angular momentum $L = I\omega$ remains constant. As the tortoise moves along a chord,its distance $r$ from the center of rotation changes. The moment of inertia $I$ of the system is given by $I = I_{	ext{platform}} + mr^2$,where $m$ is the mass of the tortoise and $r$ is its distance from the center. Initially,the tortoise is at the edge $(r = R)$,so the moment of inertia is maximum. As it moves towards the center of the chord (the point closest to the center of the platform),the distance $r$ decreases,causing the moment of inertia $I$ to decrease. Since $L = I\omega$ is constant,if $I$ decreases,the angular velocity $\omega$ must increase. After passing the point on the chord closest to the center,the distance $r$ starts increasing again,causing the moment of inertia $I$ to increase,which in turn causes the angular velocity $\omega$ to decrease. Therefore,the angular velocity first increases and then decreases.

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