$A$ wheel (rim) of mass $6 \ kg$ and radius $40 \ cm$ is rotating at a rate of $300 \ rpm$. The rotational kinetic energy of the wheel is:

Two bodies $A$ and $B$ are rotating freely with moments of inertia $I_A$ and $I_B$ respectively. Given $I_A > I_B$ and their angular momenta are equal. If $K_A$ and $K_B$ are their rotational kinetic energies,then:

$A$ flywheel of moment of inertia $0.32 \ kg \cdot m^2$ is rotated steadily at $120 \ rad/s$ by a $50 \ W$ electric motor. The kinetic energy of the flywheel is .......... $J$.

Two bodies $A$ and $B$ have moments of inertia $I_A$ and $I_B$, and angular momenta $L_A$ and $L_B$ respectively. Both of them have the same kinetic energy of rotation. The ratio of $L_A$ to $L_B$ is:

If the angular velocity of a body rotating about a given axis increases by $20 \%$,then its kinetic energy of rotation will increase by: (in $\%$)

$A$ ring of radius $r$ and mass $m$ is rotating with an angular velocity $\omega$ about an axis passing through its center and perpendicular to its plane. Its kinetic energy will be: