50 mL of each gas A and gas B takes 150 and | vedclass

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(A) According to Graham's law of effusion,the rate of effusion $r$ is inversely proportional to the square root of the molecular mass $M$: $\frac{r_A}

Vedclass · Accepted Answer

$20.25$

Vedclass · Answer

(A) According to Graham's law of effusion,the rate of effusion $r$ is inversely proportional to the square root of the molecular mass $M$: $\frac{r_A}{r_B} = \sqrt{\frac{M_B}{M_A}}$.Since $r = \frac{V}{t}$ and the volumes $V$ are equal,$\frac{r_A}{r_B} = \frac{t_B}{t_A}$.Substituting the given values: $\frac{200}{150} = \sqrt{\frac{36}{M_A}}$.Simplifying the ratio: $\frac{4}{3} = \sqrt{\frac{36}{M_A}}$.Squaring both sides: $\frac{16}{9} = \frac{36}{M_A}$.Solving for $M_A$: $M_A = \frac{36 	imes 9}{16} = \frac{324}{16} = 20.25$.

$50 \ mL$ of each gas $A$ and gas $B$ takes $150$ and $200$ seconds respectively for effusing through a pinhole under similar conditions. If the molecular mass of gas $B$ is $36$,the molecular mass of gas $A$ will be:

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