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(A) The magnetic field is directed into the paper and is increasing with time. According to Lenz's law,the induced current will create a magnetic fiel

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$B$ to $A$ and $D$ to $C$

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(A) The magnetic field is directed into the paper and is increasing with time. According to Lenz's law,the induced current will create a magnetic field that opposes this increase,meaning the induced magnetic field must be directed out of the paper. This requires the induced current in both loops to be in the anticlockwise direction.For the left loop,the anticlockwise direction implies current flows from $B$ to $A$.For the right loop,the anticlockwise direction implies current flows from $D$ to $C$.Since the area of the right loop is larger than the left loop,the induced electromotive force (emf) $\varepsilon = -\frac{d\phi}{dt} = -A \cdot \frac{dB}{dt}$ will be greater in the right loop. Consequently,the net current in the entire frame will follow the direction dictated by the larger loop,which is $B$ to $A$ in wire $AB$ and $D$ to $C$ in wire $CD$.

List-$I$	List-$II$
$A$. Magnetic induction	$I$. $MLT^{-2}A^{-2}$
$B$. Magnetic flux	$II$. $ML^2T^{-2}A^{-2}$
$C$. Magnetic permeability	$III$. $ML^0T^{-2}A^{-1}$
$D$. Self inductance	$IV$. $ML^2T^{-2}A^{-1}$

$A$ conducting wire frame is placed in a magnetic field which is directed into the paper. The magnetic field is increasing at a constant rate. The directions of induced currents in wires $AB$ and $CD$ are

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Match the List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. Magnetic induction $I$. $MLT^{-2}A^{-2}$
$B$. Magnetic flux $II$. $ML^2T^{-2}A^{-2}$
$C$. Magnetic permeability $III$. $ML^0T^{-2}A^{-1}$
$D$. Self inductance $IV$. $ML^2T^{-2}A^{-1}$

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