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(B) The time of flight of a projectile depends only on the vertical component of the initial velocity and the acceleration due to gravity.The initial

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$\frac{2V \cos 	heta}{g}$

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(B) The time of flight of a projectile depends only on the vertical component of the initial velocity and the acceleration due to gravity.The initial velocity $V$ is given at an angle $	heta$ with the vertical. Therefore,the vertical component of the velocity is $V_y = V \cos 	heta$.In an elastic collision with a vertical wall,the horizontal component of the velocity reverses direction,but the vertical component of the velocity remains unchanged.Since the vertical motion is unaffected by the collision with the vertical wall,the total time of flight is the same as that of a projectile moving without any collision.The formula for the time of flight is $T = \frac{2V_y}{g}$.Substituting $V_y = V \cos 	heta$,we get $T = \frac{2V \cos 	heta}{g}$.

$A$ ball is projected from the ground with a velocity $V$ at an angle $\theta$ to the vertical. On its path,it makes an elastic collision with a vertical wall and returns to the ground. The total time of flight of the ball is:

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