A light of wavelength 600 nm in air enters a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The frequency of light depends only on the source and remains unchanged when it travels from one medium to another.$2$. The frequency $f$ in

Vedclass · Accepted Answer

Both $(A)$ and $(C)$

Vedclass · Answer

(D) $1$. The frequency of light depends only on the source and remains unchanged when it travels from one medium to another.$2$. The frequency $f$ in air is given by $f = \frac{c}{\lambda} = \frac{3 	imes 10^8 \ m/s}{600 	imes 10^{-9} \ m} = 0.5 	imes 10^{15} \ Hz = 5 	imes 10^{14} \ Hz$.$3$. Since frequency remains constant,the frequency inside the medium is also $5 	imes 10^{14} \ Hz$.$4$. The wavelength in a medium of refractive index $\mu$ is given by $\lambda' = \frac{\lambda}{\mu}$.$5$. Given $\lambda = 600 \ nm$ and $\mu = 1.5$,we have $\lambda' = \frac{600 \ nm}{1.5} = 400 \ nm$.$6$. Thus,both statements $(A)$ and $(C)$ are correct.

$A$ light of wavelength $600 \ nm$ in air enters a medium of refractive index $1.5$. Inside the medium :

Similar Questions

When light travels from air to water,then from water to glass,then from glass to $CO_2$ gas,and finally back to air,the relation between their refractive indices is given by:

If the velocity of light in the first medium is $v_1$ and in the second medium is $v_2$,then the refractive index of the second medium with respect to the first medium is given by:

Write two definitions and equations of relative refractive index.

When can it be assumed that light moves in a straight line?

Vedclass Test Series

Exam Paper Generator

Online Exam Module