C_v and C_p denote the molar specific heat ca | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. According to Mayer's relation,$C_p - C_v = R$,where $R$ is the universal gas constant. This value is independent of the atomicity of the gas.

Vedclass · Accepted Answer

$C_p + C_v$ is larger for a diatomic ideal gas than for a monoatomic ideal gas

Vedclass · Answer

(B) $1$. According to Mayer's relation,$C_p - C_v = R$,where $R$ is the universal gas constant. This value is independent of the atomicity of the gas.$2$. The ratio $\gamma = C_p/C_v$ is given by $1 + 2/f$,where $f$ is the degree of freedom. For monoatomic gas $(f=3)$,$\gamma = 1.67$. For diatomic gas $(f=5)$,$\gamma = 1.4$. Thus,$\gamma$ decreases as atomicity increases.$3$. The sum $C_p + C_v$ can be expressed as $C_v(1 + \gamma)$. Since $C_v = fR/2$,we have $C_p + C_v = (fR/2)(1 + 1 + 2/f) = (fR/2)(2 + 2/f) = R(f + 1)$.$4$. For monoatomic gas $(f=3)$,$C_p + C_v = 4R$. For diatomic gas $(f=5)$,$C_p + C_v = 6R$. Therefore,$C_p + C_v$ is larger for a diatomic ideal gas.

$C_v$ and $C_p$ denote the molar specific heat capacities of a gas at constant volume and constant pressure,respectively. Then

Similar Questions

Explain the difference between the expressions $C_P - C_V = R$,$C_P - C_V = \frac{R}{J}$,and $C_P - C_V = \frac{r}{J}$.

If the degree of freedom of a gas is $f,$ then the ratio of two specific heats ${C_P}/{C_V}$ is given by

$310 \ J$ of heat is required to raise the temperature of $2 \ moles$ of an ideal gas at constant pressure from $25^{\circ} C$ to $35^{\circ} C$. The amount of heat required to raise the temperature of the gas through the same range at constant volume is (in $J$)

If $c_p$ and $c_v$ denote the specific heats (per unit mass) of an ideal gas of molecular weight $M$,then which of the following relations holds true,where $R$ is the molar gas constant?

The specific heat of a gas at constant pressure $(C_p)$ is more than that of the same gas at constant volume $(C_v)$ because

Vedclass Test Series

Exam Paper Generator

Online Exam Module