$2Na_2O \overset{400 \ ^oC}{\rightleftharpoons} A + 2Na$
$A + SO_2 \to Na_2SO_4$
$A + CO \to Na_2CO_3$
In the above reaction,$A$ is:

  • A
    $NaO_2$
  • B
    $Na_2O_2$
  • C
    $NaOH$
  • D
    $Na_2O_3$

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