Ph-CH(OH)-CH_3 xrightarrow{PCC} A xrightarrow | vedclass

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(A) $1$. $Ph-CH(OH)-CH_3$ is a secondary alcohol,which is oxidized by $PCC$ to form acetophenone $(A = Ph-CO-CH_3)$.$2$. Acetophenone reacts with hydr

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$Ph-CONH-CH_3, CH_3-CONH-Ph$

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(A) $1$. $Ph-CH(OH)-CH_3$ is a secondary alcohol,which is oxidized by $PCC$ to form acetophenone $(A = Ph-CO-CH_3)$.$2$. Acetophenone reacts with hydroxylamine $(NH_2OH)$ to form acetophenone oxime $(Ph-C(CH_3)=N-OH)$.$3$. Upon treatment with $H^{+}/\Delta$,the oxime undergoes Beckmann rearrangement.$4$. The Beckmann rearrangement of acetophenone oxime involves the migration of either the phenyl group or the methyl group to the nitrogen atom,resulting in two isomeric amides: $Ph-CONH-CH_3$ ($N$-methylbenzamide) and $CH_3-CONH-Ph$ ($N$-phenylacetamide).

$Ph-CH(OH)-CH_3$ $\xrightarrow{PCC} A$ $\xrightarrow[(ii) H^{+}/\Delta]{(i) NH_2OH} B + C$
In the given reaction sequence,$B$ and $C$ are:

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$Ph-CH(OH)-CH_3$ $\xrightarrow{PCC} A$ $\xrightarrow[(ii) H^{+}/\Delta]{(i) NH_2OH} B + C$In the given reaction sequence,$B$ and $C$ are: