4-Hydroxybenzenesulphonic acid is treated wit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $4$-hydroxybenzenesulphonic acid with bromine water involves electrophilic aromatic substitution. The $-OH$ group is a strong acti

Vedclass · Accepted Answer

$3, 5$-Dibromo-$4$-hydroxybenzenesulphonic acid

Vedclass · Answer

(B) The reaction of $4$-hydroxybenzenesulphonic acid with bromine water involves electrophilic aromatic substitution. The $-OH$ group is a strong activating group and is ortho/para directing. The $-SO_3H$ group is at the para position. Bromination occurs at the ortho positions relative to the $-OH$ group (positions $3$ and $5$). Since the $-SO_3H$ group is a good leaving group in the presence of water,it can be displaced by bromine,but under standard conditions with bromine water,the primary product is $3, 5$-dibromo-$4$-hydroxybenzenesulphonic acid. If excess bromine is used,the $-SO_3H$ group is replaced to form $2, 4, 6$-tribromophenol. Given the options,$3, 5$-dibromo-$4$-hydroxybenzenesulphonic acid is the specific product of the substitution.

$4$-Hydroxybenzenesulphonic acid is treated with bromine water. The product formed is -

Similar Questions

What is formed on heating an aqueous solution of benzene diazonium chloride?

Consider the following reaction:
$Phenol$ $\xrightarrow{Zn\,dust} X$ $\xrightarrow[{Anhyd.\,AlCl_3}]{CH_3Cl} Y$ $\xrightarrow{Alkaline\,KMnO_4} Z$
The product $Z$ is:

Identify the correct order of acidic strength for the following compounds:
$I$. Ortho-nitrophenol
$II$. Para-nitrophenol
$III$. Meta-nitrophenol

Major product of reaction :

Which of the following compounds has the highest boiling point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module