PhCHO xrightarrow{OH^{-}} PhCH_2OH + PhCOO^{- | vedclass

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(C) The given reaction is the $Cannizzaro$ reaction,where benzaldehyde $(PhCHO)$ undergoes self-oxidation and reduction in the presence of a concentra

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both $A$ $\&$ $B$

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(C) The given reaction is the $Cannizzaro$ reaction,where benzaldehyde $(PhCHO)$ undergoes self-oxidation and reduction in the presence of a concentrated base $(OH^-)$.In this reaction,one molecule of benzaldehyde is reduced to benzyl alcohol $(PhCH_2OH)$ and another molecule is oxidized to benzoate ion $(PhCOO^-)$.Since both oxidation and reduction occur simultaneously in the same species,it is a disproportionation reaction.Since it involves both oxidation and reduction,it is also a redox reaction.Therefore,the reaction is both a redox reaction and a disproportionation reaction.

$PhCHO \xrightarrow{OH^{-}} PhCH_2OH + PhCOO^{-}$
This reaction is an example of -

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$PhCHO \xrightarrow{OH^{-}} PhCH_2OH + PhCOO^{-}$This reaction is an example of -