CH_3CH(I)_2 xrightarrow{KCN} xrightarrow[Delt | vedclass

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Question

(D) The reaction proceeds as follows:$1$. $CH_3CH(I)_2$ reacts with $KCN$ to form $CH_3CH(CN)_2$ via nucleophilic substitution.$2$. Acidic hydrolysis

Vedclass · Accepted Answer

Propionic acid

Vedclass · Answer

(D) The reaction proceeds as follows:$1$. $CH_3CH(I)_2$ reacts with $KCN$ to form $CH_3CH(CN)_2$ via nucleophilic substitution.$2$. Acidic hydrolysis $(H_3O^{ })$ of $CH_3CH(CN)_2$ converts the cyano groups into carboxylic acid groups,yielding $CH_3CH(COOH)_2$ (Ethane$-1,1-$dicarboxylic acid).$3$. Upon heating $(\Delta)$,the geminal dicarboxylic acid undergoes decarboxylation to lose one $CO_2$ molecule,resulting in $CH_3CH_2COOH$ (Propionic acid).

$CH_3CH(I)_2$ $\xrightarrow{KCN}$ $\xrightarrow[\Delta]{H_3O^{+}} ?$ Here the end product would be

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