$X$ $\xrightarrow{N_2, \Delta} Y$ $\xrightarrow{H_2O} Z$ (colourless gas) $\xrightarrow{CuSO_4} T$ (blue colour)
Then,substances $Y$ and $T$ are
Then,substances $Y$ and $T$ are
- A$Y = Mg_3N_2$ and $T = CuSO_4 \cdot 5H_2O$
- B$Y = Mg_3N_2$ and $T = CuSO_4 \cdot 4NH_3$
- C$Y = Mg(NO_3)_2$ and $T = CuO$
- D$Y = MgO$ and $T = CuSO_4 \cdot 4NH_3$
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