I. 4FeCr_2O_4 + 16NaOH + 7O_2 rightarrow 8Na_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The extraction of chromium from chromite ore $(FeCr_2O_4)$ involves the following steps:Step $I$: The chromite ore is fused with sodium hydroxide

Vedclass · Accepted Answer

$Na_2CrO_4, H_2SO_4$

Vedclass · Answer

(A) The extraction of chromium from chromite ore $(FeCr_2O_4)$ involves the following steps:Step $I$: The chromite ore is fused with sodium hydroxide in the presence of air to form sodium chromate $(Na_2CrO_4)$.$4FeCr_2O_4 + 16NaOH + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8H_2O$Here,$(A) = Na_2CrO_4$.Step $II$: The yellow solution of sodium chromate is acidified with concentrated sulfuric acid $(H_2SO_4)$ to convert it into orange sodium dichromate $(Na_2Cr_2O_7)$.$2Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O$Here,$(B) = H_2SO_4$.Thus,the compounds $(A)$ and $(B)$ are $Na_2CrO_4$ and $H_2SO_4$ respectively.

$I$. $4FeCr_2O_4 + 16NaOH + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8H_2O$ (where $A = Na_2CrO_4$)
$II$. $2Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O$ (where $B = H_2SO_4$)
Compounds $(A)$ and $(B)$ are :

Similar Questions

When dilute $H_2SO_4$ is added to an aqueous solution of potassium chromate,the yellow color of the solution turns to orange. What does this indicate?

Metre scales are made up of which alloy?

The most basic hydroxide among the following is

Which of the following alloys is used in the construction of the outer fuselage of ultra-high-speed aircraft?

Which of the following is used in the manufacture of high refractive index optical glass for cameras?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$I$. $4FeCr_2O_4 + 16NaOH + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8H_2O$ (where $A = Na_2CrO_4$)$II$. $2Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O$ (where $B = H_2SO_4$)Compounds $(A)$ and $(B)$ are :