A xleftarrow{CH_3OH, CH_3O^{-}} (1-methyl-6-o | vedclass

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(A) The starting material is $1$-methyl-$6$-oxabicyclo$[3.1.0]$hexane. $1$. Reaction with $CH_3OH/CH_3O^{-}$ (Basic medium): This is an $S_N2$ reactio

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(A) The starting material is $1$-methyl-$6$-oxabicyclo$[3.1.0]$hexane. $1$. Reaction with $CH_3OH/CH_3O^{-}$ (Basic medium): This is an $S_N2$ reaction. The nucleophile $CH_3O^{-}$ attacks the less sterically hindered carbon (the $CH_2$ group of the epoxide ring). This results in the opening of the epoxide ring with the $OCH_3$ group at the less substituted carbon and the $OH$ group at the more substituted carbon (tertiary carbon). $2$. Reaction with $CH_3OH/H_2SO_4$ (Acidic medium): This is an $S_N1$-like reaction. The epoxide oxygen is protonated,making the ring carbons more electrophilic. The more substituted carbon (tertiary carbon) can better stabilize the partial positive charge in the transition state. Therefore,the nucleophile $CH_3OH$ attacks the more substituted carbon,resulting in the $OCH_3$ group at the tertiary carbon and the $OH$ group at the less substituted carbon.

Column-$I$ (Reaction)	Column-$II$ (Bond broken)
$(A)$ $RCH_2OH \xrightarrow{CrO_3} RCHO$	$(i)$ $C-O$ bond breaks.
$(B)$ Phenol $\xrightarrow{HNO_3}$ $p$-Nitrophenol + $o$-Nitrophenol	(ii) $O-H$ bond breaks.
$(C)$ Phenol + $NaOH \rightarrow$ Sodium phenoxide + $H_2O$	(iii) $O-H$ and $C-H$ bonds break.
$(D)$ $CH_3CH_2CH_2OH \xrightarrow{H_2SO_4, \Delta} CH_3CH=CH_2$	(iv) $C-H$ bond breaks.

$A$ $\xleftarrow{CH_3OH, CH_3O^{-}}$ ($1$-methyl$-6-$oxabicyclo[$3.1$.$0$]hexane) $\xrightarrow{CH_3OH, H_2SO_4}$ $B$
$A$ $\&$ $B$ are :

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$A$ $\xleftarrow{CH_3OH, CH_3O^{-}}$ ($1$-methyl$-6-$oxabicyclo[$3.1$.$0$]hexane) $\xrightarrow{CH_3OH, H_2SO_4}$ $B$ $A$ $\&$ $B$ are :