C_6H_6 xrightarrow{CH_3COCl/AlCl_3} A xrighta | vedclass

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(B) $1$. The reaction of benzene $(C_6H_6)$ with acetyl chloride $(CH_3COCl)$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reac

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Ethyl benzene

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(B) $1$. The reaction of benzene $(C_6H_6)$ with acetyl chloride $(CH_3COCl)$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reaction. This produces acetophenone $(C_6H_5COCH_3)$ as product $A$.$2$. The reaction of acetophenone $(C_6H_5COCH_3)$ with $Zn-Hg/HCl$ is a Clemmensen reduction,which reduces the carbonyl group $(>C=O)$ to a methylene group $(-CH_2-)$.$3$. The reduction of acetophenone yields ethyl benzene $(C_6H_5CH_2CH_3)$ as the final product $B$.

$C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} A$ $\xrightarrow{Zn-Hg/HCl} B$
The end product in the above sequence is:

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$C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} A$ $\xrightarrow{Zn-Hg/HCl} B$ The end product in the above sequence is: