CuSO_{4(aq)} + 4NH_3 rightarrow X, then X is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction between aqueous copper$(II)$ sulfate and ammonia is: $CuSO_{4(aq)} + 4NH_3(aq) \rightarrow [Cu(NH_3)_4]SO_4(aq)$.Here,the complex ion

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) The reaction between aqueous copper$(II)$ sulfate and ammonia is: $CuSO_{4(aq)} + 4NH_3(aq) \rightarrow [Cu(NH_3)_4]SO_4(aq)$.Here,the complex ion $X$ is $[Cu(NH_3)_4]^{2+}$.$1$. The electronic configuration of $Cu^{2+}$ is $[Ar]3d^9$,which contains one unpaired electron,making it paramagnetic.$2$. Due to the presence of an unpaired electron in the $d$-orbital,it undergoes $d-d$ transition,making the complex coloured (deep blue).Therefore,all the given statements are correct.

Column-$I$	Column-$II$
$A$. $[Co(NH_3)_4(H_2O)_2]Cl_2$	$p$. geometrical isomers
$B$. $[Pt(NH_3)_2Cl_2]$	$q$. paramagnetic
$C$. $[Co(H_2O)_5Cl]Cl$	$r$. diamagnetic
$D$. $[Ni(H_2O)_6]Cl_2$	$s$. metal ion with $+2$ oxidation state

$CuSO_{4(aq)} + 4NH_3 \rightarrow X,$ then $X$ is

Similar Questions

Total number of molecules/species from the following which will be paramagnetic is $........$
$O_2, O_2^{+}, O_2^{-}, NO, NO_2, CO, K_2[NiCl_4], [Co(NH_3)_6]Cl_3, K_2[Ni(CN)_4]$

Which statement is wrong?

The configurations for the complex $[Co(en)(NH_3)_2Br_2]^+$ are shown. Which of the following statements is incorrect?

Given below are two statements:
Statement $I$: $PF_5$ and $BrF_5$ both exhibit $sp^3 d$ hybridisation.
Statement $II$: Both $SF_6$ and $[Co(NH_3)_6]^{3+}$ exhibit $sp^3 d^2$ hybridisation.
In the light of the above statements,choose the correct answer from the options given below:

Vedclass Test Series

Exam Paper Generator

Online Exam Module